3a^2+15a+12=0

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Solution for 3a^2+15a+12=0 equation: 



3a^2+15a+12=0

a = 3; b = 15; c = +12;
Δ = b2-4ac
Δ = 152-4·3·12
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{81}=9$


$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-9}{2*3}=\frac{-24}{6}
=-4
$


$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+9}{2*3}=\frac{-6}{6}
=-1
$

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